Get tutorials Raspberry Pi Super Kit V2.0 for RaspberryPi

Lesson 1 Blinking LED


In this lesson, we will learn how to program Raspberry Pi to make an LED blink. You can play numerous tricks with an LED as you want. Now get to start and you will enjoy the fun of DIY at once!


- 1* Raspberry Pi

- 1* Breadboard

- 1* LED

- 1* Resistor (220Ω)

- Jumper wires


Semiconductor light-emitting diode is a type of component which can turn electric energy into light energy via PN junctions. By wavelength, it can be categorized into laser diode, infrared light-emitting diode and visible light-emitting diode which is usually known as light-emitting diode (LED).

When 2V-3V forward voltage is supplied to an LED, it will blink only if forward currents flow through the LED. Usually there are red, yellow, green, blue and color-changing LEDs which change color with different voltages. LEDs are widely used due to their low operating voltage, low current, luminescent stability and small size.

LEDs are diodes too. Hence they have a voltage drop which usually varies from 1V to 3V depending on their types.Generally they brighten if supplied with a 5mA-30mA current,and we usually use 10mA-20mA.Thus when an LED is used ,it is necessary to connect a current-limiting resistor to protect it from being burnt.



In this experiment, connect a 220Ω resistor to the anode of the LED,then the resistor to 3.3 V,and connect the cathode of the LED to GPIO0 (See Raspberry Pi Pin Number Introduction). Write 1 to GPIO0, and the LED will stay off; write 0 to GPIO0, and then the LED will blink,just as indicated by the principle above.

Experimental Procedures

Step 1: Build the circuit


For C language users:

Step 2: Change directory

cd /home/pi/Sunfounder_SuperKit_C_code_for_RaspberryPi/01_LED/

Step 3: Compile

        gcc led.c –o led –lwiringPi

Step 4: Run

        sudo ./led

For Python users:

Step 2: Change directory

cd /home/pi/Sunfounder_SuperKit_ Python_code_for_RaspberryPi/

Step 3: Run

          sudo python

Now, you should see the LED blink.


Further Exploration

If you want the LED to speed up the blinking, just change the delay time. For example, change the time to delay (200) in the program, recompile and run, and then you will see the LED blink faster.


Raspberry Pi packages many low-level detail designs, which enable you to explore your own apps more conveniently. Maybe that is the charm of Raspberry Pi.

Now you have already learnt how to use the Raspberry Pi GPIO0 to blink an LED. Keep moving to the next contents. 

Tips: For any TECHNICAL questions, add a topic under FORUMsection on our website and we'll reply as soon as possible. For NON-TECH questions like order issues, please

C Code

* Filename    : led.c
* Description : Make an led blinking.
* Author      : Robot
* E-mail      :
* website     :
* Date        : 2014/08/27
#include <wiringPi.h>
#include <stdio.h>

#define  LedPin    0

int main(void)
	if(wiringPiSetup() == -1){ //when initialize wiring failed,print messageto screen
		printf("setup wiringPi failed !");
		return 1; 
	printf("linker LedPin : GPIO %d(wiringPi pin)\n",LedPin); //when initialize wiring successfully,print message to screen
	pinMode(LedPin, OUTPUT);

			digitalWrite(LedPin, LOW);  //led on
			printf("led on...\n");
			digitalWrite(LedPin, HIGH);  //led off
			printf("...led off\n");

	return 0;

Python Code

#!/usr/bin/env python
import RPi.GPIO as GPIO
import time

LedPin = 11    # pin11

def setup():
	GPIO.setmode(GPIO.BOARD)       # Numbers GPIOs by physical location
	GPIO.setup(LedPin, GPIO.OUT)   # Set LedPin's mode is output
	GPIO.output(LedPin, GPIO.HIGH) # Set LedPin high(+3.3V) to off led

def loop():
	while True:
		print '...led on'
		GPIO.output(LedPin, GPIO.LOW)  # led on
		print 'led off...'
		GPIO.output(LedPin, GPIO.HIGH) # led off

def destroy():
	GPIO.output(LedPin, GPIO.HIGH)     # led off
	GPIO.cleanup()                     # Release resource

if __name__ == '__main__':     # Program start from here
	except KeyboardInterrupt:  # When 'Ctrl+C' is pressed, the child program destroy() will be  executed.



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Apr 01 2017 at 10:16 am

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